A square painting has a diagonal of 44 in. Lorraine wants to frame the picture. How many inches of frame will she need? Round to the nearest inch
By
putra
—
Mathematics
A square painting has a diagonal of 44 in. Lorraine wants to frame the picture. How many inches of frame will she need? Round to the nearest inch - Hello Friend question and answers, In sharing this time titled A square painting has a diagonal of 44 in. Lorraine wants to frame the picture. How many inches of frame will she need? Round to the nearest inch, in helping to answer a question or help learning, hopefully content posting subject matter that I share this you can understand, if there are any difficulties please to comment.
Your Question : A square painting has a diagonal of 44 in. Lorraine wants to frame the picture. How many inches of frame will she need? Round to the nearest inch
You are currently reading the article about lessons A square painting has a diagonal of 44 in. Lorraine wants to frame the picture. How many inches of frame will she need? Round to the nearest inch and this lesson url permalink of the article was https://choosequestion.blogspot.com/2016/07/a-square-painting-has-diagonal-of-44-in.html Hopefully this question and answer article can give good answers, good learning.
A square painting has a diagonal of 44 in. Lorraine wants to frame the picture. How many inches of frame will she need? Round to the nearest inch
Answer:
The square has a diagonal of 44 inches.
In order to get the side, we need to use the pythagorean equation.
Diagonal (d) ^ 2 = side^2 + side ^ 2
Diagonal (d) ^ 2 = 2side (s)^2
d^2 = 2s^2
44^2 = 2s^2
1936 = 2s^2
2s^2 = 1936
s^2 = 968
s = 31.11 inches
The length of the side is approximately 31 inches.
Perimeter = 4*s
Perimeter = 4 * 31
Perimeter = 124 inches
So she need a total of 124 inches to frame the square.
The square has a diagonal of 44 inches.
In order to get the side, we need to use the pythagorean equation.
Diagonal (d) ^ 2 = side^2 + side ^ 2
Diagonal (d) ^ 2 = 2side (s)^2
d^2 = 2s^2
44^2 = 2s^2
1936 = 2s^2
2s^2 = 1936
s^2 = 968
s = 31.11 inches
The length of the side is approximately 31 inches.
Perimeter = 4*s
Perimeter = 4 * 31
Perimeter = 124 inches
So she need a total of 124 inches to frame the square.
The Article A square painting has a diagonal of 44 in. Lorraine wants to frame the picture. How many inches of frame will she need? Round to the nearest inch
The answer to question A square painting has a diagonal of 44 in. Lorraine wants to frame the picture. How many inches of frame will she need? Round to the nearest inch, Hopefully can give benefits to all. well, If you guys are still looking for another answer use the menu search or look at the related articles.
You are currently reading the article about lessons A square painting has a diagonal of 44 in. Lorraine wants to frame the picture. How many inches of frame will she need? Round to the nearest inch and this lesson url permalink of the article was https://choosequestion.blogspot.com/2016/07/a-square-painting-has-diagonal-of-44-in.html Hopefully this question and answer article can give good answers, good learning.