A line passes through the points (p, a) and (p, –a) where p and a are real numbers. If p=0, what is the y-intercept?

A line passes through the points (p, a) and (p, –a) where p and a are real numbers. If p=0, what is the y-intercept? - Hello Friend question and answers, In sharing this time titled A line passes through the points (p, a) and (p, –a) where p and a are real numbers. If p=0, what is the y-intercept?, in helping to answer a question or help learning, hopefully content posting subject matter that I share this you can understand, if there are any difficulties please to comment.

Your Question : A line passes through the points (p, a) and (p, –a) where p and a are real numbers. If p=0, what is the y-intercept?

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A line passes through the points (p, a) and (p, –a) where p and a are real numbers. If p=0, what is the y-intercept?

 Explain your reasoning

A line passes through the points (p, a) and (p, –a) where p and a are real numbers. If p=0, what is the y-intercept?
Answer:

A line passes through the points (p, a) and (p, –a) where p and a are real numbers. If p=0, what is the y-intercept? Explain your reasoning.

p - as "x" never changes with the value of "y", so no matter what y is, x is always "p", so when y is 0, x = p

slope of the line
change in y over the change in x
(-a - a) / (p - p) = infinity - or a vertical line
equation of the line
y = p
slope of a line perpendicular to the given line
inverse of the orig slope or (p - p)/(-a - a) = 0



The Article A line passes through the points (p, a) and (p, –a) where p and a are real numbers. If p=0, what is the y-intercept?

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