Solve for x:-ax+3b>5
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putra
—
Mathematics
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Your Question : Solve for x:-ax+3b>5
Answer:
Our current equation is:
-ax + 3b > 5
Our objective is to solve for x, so let's first get -ax by itself.
Subtract 3b from both sides.
-ax > -3b + 5
Now, we have -a multiplying x, so we need to perform the opposite order of operations (like previously shown with 3b).
Divide both sides by -a.
Remember to flip the inequality when multiplying or dividing by a negative.
x <_ (-3b + 5)/-a is your final answer.
You are currently reading the article about lessons Solve for x:-ax+3b>5 and this lesson url permalink of the article was https://choosequestion.blogspot.com/2017/07/solve-for-x-ax3b5.html Hopefully this question and answer article can give good answers, good learning.
Solve for x:-ax+3b>5
Our current equation is:
-ax + 3b > 5
Our objective is to solve for x, so let's first get -ax by itself.
Subtract 3b from both sides.
-ax > -3b + 5
Now, we have -a multiplying x, so we need to perform the opposite order of operations (like previously shown with 3b).
Divide both sides by -a.
Remember to flip the inequality when multiplying or dividing by a negative.
x <_ (-3b + 5)/-a is your final answer.
The Article Solve for x:-ax+3b>5
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You are currently reading the article about lessons Solve for x:-ax+3b>5 and this lesson url permalink of the article was https://choosequestion.blogspot.com/2017/07/solve-for-x-ax3b5.html Hopefully this question and answer article can give good answers, good learning.