An analysis, the compound x contained 40,68% carbon,5,08% Hydrogen and 52,24% oxygen determine the empirical formula of the compound x
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Your Question : An analysis, the compound x contained 40,68% carbon,5,08% Hydrogen and 52,24% oxygen determine the empirical formula of the compound x
Answer:
You can assume that you are starting with 100 grams of the compound. Then...
40.68% C = 40.68 grams. Divided by atomic mass of 12 = 3.39 moles of C
8.05 %H = 8.05 grams. Divided by atomic mass 1 = 8.05 moles H
52.24% O = 52.24 grams. Divided by atomic mass 16 = 3.265 moles O
Divide through by the smallest value of 3.265 to get
moles C = 3.39/3.265 = 1.0 moles C
moles H = 5.08/3.265 = 1.5 moles H
moles O = 3.265/3.265 = 1 moles O
To get the H to be a whole number, multiply by 2 to get 1.5 x 2 = 3
then multiply all others by 2 also to get 2 C and 2 O
Finally, you have C2H3O2
You are currently reading the article about lessons An analysis, the compound x contained 40,68% carbon,5,08% Hydrogen and 52,24% oxygen determine the empirical formula of the compound x and this lesson url permalink of the article was https://choosequestion.blogspot.com/2016/12/an-analysis-compound-x-contained-4068.html Hopefully this question and answer article can give good answers, good learning.
An analysis, the compound x contained 40,68% carbon,5,08% Hydrogen and 52,24% oxygen determine the empirical formula of the compound x
You can assume that you are starting with 100 grams of the compound. Then...
40.68% C = 40.68 grams. Divided by atomic mass of 12 = 3.39 moles of C
8.05 %H = 8.05 grams. Divided by atomic mass 1 = 8.05 moles H
52.24% O = 52.24 grams. Divided by atomic mass 16 = 3.265 moles O
Divide through by the smallest value of 3.265 to get
moles C = 3.39/3.265 = 1.0 moles C
moles H = 5.08/3.265 = 1.5 moles H
moles O = 3.265/3.265 = 1 moles O
To get the H to be a whole number, multiply by 2 to get 1.5 x 2 = 3
then multiply all others by 2 also to get 2 C and 2 O
Finally, you have C2H3O2
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You are currently reading the article about lessons An analysis, the compound x contained 40,68% carbon,5,08% Hydrogen and 52,24% oxygen determine the empirical formula of the compound x and this lesson url permalink of the article was https://choosequestion.blogspot.com/2016/12/an-analysis-compound-x-contained-4068.html Hopefully this question and answer article can give good answers, good learning.